Problem 2- A car is stopped at a traffic light. It then travels along a straight road so that its position from the light is given by x(t) 2.5t - 0.13t^2 in meters.

Question

c. What is the position of the particle when it reverses its motion?

Answer 1

x=2.5t-1.3t^2
I assume you have some calculus, so max x is the derivative of x set to zero, so

0=2.5-2.6t solve for t, then put that in the original equation and solve for x.

Answer 2

Thank you