Asked by R
Problem 1: The PDF of exp(X)
(6/6 points)
Let X be a random variable with PDF fX. Find the PDF of the random variable Y=eX for each of the following cases:
For general fX, when y>0, fY(y)=
Solution: f_x(ln(y))/y
When fX(x) = {1/3,0,if −2<x≤1,otherwise,
we have fY(y) = {g(y),0,if a<y≤b,otherwise.
Give a formula for g(y) and the values of a and b using standard notation . (In your answers, you may use the symbol 'e' to denote the base of the natural logarithm.)
Solution: g(y) = 1/(3*y)
a = e^(-2)
b = e
When fX(x) = {2e−2x,0,if x>0,otherwise,
we have fY(y) = {g(y),0,if a<y,otherwise.
Give a formula for g(y) and the value of a using the standard notation .
Solution: g(y) = 2/(y^(3))
a= 1
When X is a standard normal random variable, we have, for y>0, fY(y)=
Solution: 1/sqrt(2pi) * (e^(-ln(x))^2/2)/y
Enjoj :-)
(6/6 points)
Let X be a random variable with PDF fX. Find the PDF of the random variable Y=eX for each of the following cases:
For general fX, when y>0, fY(y)=
Solution: f_x(ln(y))/y
When fX(x) = {1/3,0,if −2<x≤1,otherwise,
we have fY(y) = {g(y),0,if a<y≤b,otherwise.
Give a formula for g(y) and the values of a and b using standard notation . (In your answers, you may use the symbol 'e' to denote the base of the natural logarithm.)
Solution: g(y) = 1/(3*y)
a = e^(-2)
b = e
When fX(x) = {2e−2x,0,if x>0,otherwise,
we have fY(y) = {g(y),0,if a<y,otherwise.
Give a formula for g(y) and the value of a using the standard notation .
Solution: g(y) = 2/(y^(3))
a= 1
When X is a standard normal random variable, we have, for y>0, fY(y)=
Solution: 1/sqrt(2pi) * (e^(-ln(x))^2/2)/y
Enjoj :-)
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