Asked by jasort20
Problem #1
subtract. Express your answer in simplest form
(3x)/(18) minus (x)/(18)
MY steps:
(3x-x)/(18) = (2x)/(18)
and answer:
(2x)/(18)
Problem #18
write in simplest form.
(3x^5)/(15x^12)
My steps:
(3)/(15) = .60
x^5-12 = x^-7
so my answer is: .60x^-7
Problem #21
Add. express your answer in simplest form.
(x)/(6) + (3x)/(6)
= (x+3x)/(6)
my answer= (4x)/(6)
#1 : Yes, but one more step. You can take the 2 and the 18 and figure out how to reduce those. So it would be 1x/9 (Or just x/9)
#2: 3/15 = .2 On a technical level, .2x^-7 would be a correct answer. But not in its simplest form. 1/5 is the same as 3/15, so we can write it like:
1/5x^7
#3 One more step. What can you do with the 4 and 6? (Clue: Look at my reply to question #1 above)
my question is how is the answer
1/5x^7
if the exponent is a negative 7? and you have it as a positive 7
and for problem # 3
would then the last step be:
2x/3
subtract. Express your answer in simplest form
(3x)/(18) minus (x)/(18)
MY steps:
(3x-x)/(18) = (2x)/(18)
and answer:
(2x)/(18)
Problem #18
write in simplest form.
(3x^5)/(15x^12)
My steps:
(3)/(15) = .60
x^5-12 = x^-7
so my answer is: .60x^-7
Problem #21
Add. express your answer in simplest form.
(x)/(6) + (3x)/(6)
= (x+3x)/(6)
my answer= (4x)/(6)
#1 : Yes, but one more step. You can take the 2 and the 18 and figure out how to reduce those. So it would be 1x/9 (Or just x/9)
#2: 3/15 = .2 On a technical level, .2x^-7 would be a correct answer. But not in its simplest form. 1/5 is the same as 3/15, so we can write it like:
1/5x^7
#3 One more step. What can you do with the 4 and 6? (Clue: Look at my reply to question #1 above)
my question is how is the answer
1/5x^7
if the exponent is a negative 7? and you have it as a positive 7
and for problem # 3
would then the last step be:
2x/3
Answers
Answered by
saryah
4 1×4 2×2
10 1×10,2×5 in division
10 1×10,2×5 in division
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