Prize No prize

mini 9 6
regular 5 9
jumbo 7 8
what is the probability that a randomly selected box of cereal is jumbo size given that the box of cereal contains a prize?

1 answer

To find the probability that a randomly selected box of cereal is jumbo size given that the box contains a prize, we use the concept of conditional probability.

Let:

  • A = the event that a box is jumbo size.
  • B = the event that a box contains a prize.

We want to find \( P(A | B) \), the probability that a box is jumbo size given that it contains a prize. This can be calculated using the formula:

\[ P(A | B) = \frac{P(A \cap B)}{P(B)} \]

Step 1: Find \( P(A \cap B) \) (the probability that a box is both jumbo size and contains a prize):

From the given data, the number of jumbo boxes that contain a prize is 7.

Step 2: Find \( P(B) \) (the total probability that a box contains a prize):

To find \( P(B) \), we need to sum the boxes that contain a prize across all sizes:

  • Mini with prize: 9
  • Regular with prize: 5
  • Jumbo with prize: 7

Total boxes with a prize = \( 9 + 5 + 7 = 21 \).

Step 3: Find the total number of boxes:

Now, let's calculate the total number of boxes, both with and without a prize:

  • Mini without prize: 6
  • Regular without prize: 9
  • Jumbo without prize: 8

Total boxes = \( 9 + 6 + 5 + 9 + 7 + 8 = 44 \).

Step 4: Calculate \( P(B) \):

Now we have the total boxes with a prize (21) and the total number of boxes (44):

\[ P(B) = \frac{\text{Total with prize}}{\text{Total boxes}} = \frac{21}{44} \]

Step 5: Calculate \( P(A \cap B) \):

The probability that a box is jumbo and contains a prize is the favorable outcome (7) divided by total boxes (44):

\[ P(A \cap B) = \frac{7}{44} \]

Step 6: Calculate \( P(A | B) \):

Now we can substitute back into our conditional probability formula:

\[ P(A | B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{7}{44}}{\frac{21}{44}} = \frac{7}{21} = \frac{1}{3} \]

Thus, the probability that a randomly selected box of cereal is jumbo size given that the box contains a prize is \( \frac{1}{3} \).