Prime factorization of 56

Answer 1

To find the prime factorization of 56, we can divide it by the smallest prime numbers:

1. Start by dividing by 2 (the smallest prime number): \[ 56 \div 2 = 28 \]

2. Divide 28 by 2: \[ 28 \div 2 = 14 \]

3. Divide 14 by 2: \[ 14 \div 2 = 7 \]

4. Now, 7 is a prime number, so we cannot divide it further.

Putting it all together, we have: \[ 56 = 2 \times 2 \times 2 \times 7 \]

This can also be expressed using exponents as: \[ 56 = 2^3 \times 7^1 \]

Thus, the prime factorization of 56 is \(2^3 \times 7\).