Prepare 0.03 mole fraction solution of NaOH in water
Total volume of solution is 100ml
2 answers
How to prepare?
You want XNaOH = 0.03. Then
0.03 = mols NaOH/[mols NaOH +(mols H2O-mols NaOH)]
If you let y stand for mols NaOH, this becomes
0.03 = y/[y+(100/18)-y]
Solve for y = mols NaOH. Post your work if you get stuck.
0.03 = mols NaOH/[mols NaOH +(mols H2O-mols NaOH)]
If you let y stand for mols NaOH, this becomes
0.03 = y/[y+(100/18)-y]
Solve for y = mols NaOH. Post your work if you get stuck.