Predict the volume (in litres) occupied by 1.57 g of nitrogen stored at 18°C and a pressure of 207 kPa.

Answer 1

To find the volume occupied by 1.57 g of nitrogen gas at 18°C and 207 kPa, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in Pa)
V = volume (in m^3)
n = number of moles
R = ideal gas constant (8.314 J/mol*K)
T = temperature (in K)

First, we need to convert the given mass of nitrogen into moles:

molar mass of nitrogen (N2) = 28.02 g/mol
n = 1.57 g / 28.02 g/mol = 0.056 mol

Next, we need to convert the given temperature into Kelvin:

T = 18°C + 273.15 = 291.15 K

Now, we can substitute the values into the ideal gas law equation:

V = (nRT) / P
V = (0.056 mol * 8.314 J/mol*K * 291.15 K) / 207000 Pa
V = 0.261 m^3

Now, we need to convert the volume from cubic meters to liters by multiplying by 1000:

V = 0.261 m^3 * 1000 L/m^3
V = 261 L

Therefore, the volume occupied by 1.57 g of nitrogen gas at 18°C and 207 kPa is 261 liters.