ΔG0 < 0 and ΔSuniverse > 0
At -10℃ and 1 atm, water is not at its normal freezing point of 0℃. Since the process is not at equilibrium, ΔG0 will be negative because the system has a tendency to move towards a lower free energy state. ΔSuniverse will be positive as the entropy of the universe increases due to the formation of solid water molecules from liquid water molecules.
Predict the sign of ΔG0 and ΔSuniverse for water freezing at -10℃ and 1 atm. Note that the normal freezing point of water is 0℃.
ΔG0 > 0 and ΔSuniverse > 0
ΔG0 < 0 and ΔSuniverse < 0
ΔG0 = 0 and ΔSuniverse = 0
ΔG0 > 0 and ΔSuniverse < 0
ΔG0 < 0 and ΔSuniverse > 0
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