Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equation is balanced.

Question

HClO3+KOH

Answer 1

To predict the products of the reaction between \( \text{HClO}_3 \) (chloric acid) and \( \text{KOH} \) (potassium hydroxide), we first recognize that this is a neutralization reaction between an acid and a base, which typically forms water and a salt.

Here is the general form of the reaction:
\[ \text{HClO}_3 + \text{KOH} \rightarrow \text{H}_2\text{O} + \text{KClO}_3 \]

Now let's balance the equation. We currently have:

- \( \text{HClO}_3 + \text{KOH} \rightarrow \text{H}_2\text{O} + \text{KClO}_3 \)

Checking the atoms on both sides:
- Hydrogens: 1 (from \( \text{HClO}_3 \)) + 1 (from \( \text{KOH} \)) on the left, and 2 on the right (in \( \text{H}_2\text{O} \))
- Chlorines: 1 on both sides (in \( \text{HClO}_3 \) and \( \text{KClO}_3 \))
- Oxygens: 3 (from \( \text{HClO}_3 \)) + 1 (from \( \text{KOH} \)) on the left, and 1 (from \( \text{H}_2\text{O} \)) + 3 (from \( \text{KClO}_3 \)) on the right
- Potassiums: 1 (from \( \text{KOH} \)) on both sides

The equation is already balanced:

\[ \text{HClO}_3 + \text{KOH} \rightarrow \text{H}_2\text{O} + \text{KClO}_3 \]

So, the balanced equation for the reaction is:
\[ \text{HClO}_3 + \text{KOH} \rightarrow \text{H}_2\text{O} + \text{KClO}_3 \]

The products of the reaction are water (\( \text{H}_2\text{O} \)) and potassium chlorate (\( \text{KClO}_3 \)).