Precalc

Question

(1+i)^3
and
the cube root of 8i

Answer 1

(1+i) = (√2,pi/4)
so, (1+i)^3 = (2√2,3pi/4) = (-2+2i)

8i = (8,pi/2)
(8i)^(1/3) = (2,pi/6) = (√3+i)