📝Practice Screen #29.

Drag and drop the points to graph and solve the system of equations.


y =
2
3​x−2 (blue line)

=-\frac{1}{2}x+
y=−
1
2​x+5 (red line)

✅ CORRECT!

Enter the solution:

1 answer

To solve the system of equations graphically, let’s first identify the two equations we will be working with:

  1. Blue Line: \( y = \frac{2}{3}x - 2 \)
  2. Red Line: \( y = -\frac{1}{2}x + 5 \)

To find the solution of the system, we need to determine the point where these two lines intersect.

Step 1: Find the Intersection Point

To find the point of intersection, set the two equations equal to each other:

\[ \frac{2}{3}x - 2 = -\frac{1}{2}x + 5 \]

Step 2: Solve for \( x \)

Multiply every term by 6 to eliminate the fractions:

\[ 6 \left(\frac{2}{3}x\right) - 6(2) = 6\left(-\frac{1}{2}x\right) + 6(5) \]

This simplifies to:

\[ 4x - 12 = -3x + 30 \]

Now, combine like terms:

\[ 4x + 3x = 30 + 12 \]

\[ 7x = 42 \]

Now, divide by 7:

\[ x = 6 \]

Step 3: Substitute \( x \) Back to Find \( y \)

Now, we can substitute \( x = 6 \) back into either equation to find \( y \). Let’s use the blue line equation:

\[ y = \frac{2}{3}(6) - 2 \]

Calculating this gives:

\[ y = 4 - 2 = 2 \]

Solution

Thus, the solution to the system of equations, or the point of intersection, is:

(6, 2)

You can then enter the solution as:

Enter the solution: \( (6, 2) \)