PQR is a triangle and PX is perpendicular to QR at X.

Question

Given that PR= 6cm, RX=4cm and RQ=9cm, calculate PQ.
Leave your answer in surd form?

Answer 1

Did you make your sketch??
I get PX^2 + 4^2 = 6^2
PX =

now in the other triangle:
PQ^2 = 5^2 + PX^2 , but you know PX^2, so its easy from here