dHsoln = dHhydration - lattice energy
dHsoln = -155 kcal/mol -(-164.8 kcal/mol
Solve for dHsoln = about 8 kcal/mol and I would convert that to J/mol. Then
1 mol KNO3 x (105,000/converted 8.3, then convert mols KNO3 to grams KNO3. If I didn't slip on my calculator that is about 300 g KNO3 but check my work carefully.
Potassium nitrate has a lattice energy of -163.8 kcal/mol and a heat of hydration of -155.5 kcal/mol.
How much potassium nitrate has to dissolve in water to absorb 105 kJ of heat?
2 answers
DrBob the end of your explanation is vague as all sweet mercy
1 answer