Potassium iodide is prepared by the reaction of hydroiodic acid and potassium hydrogen carbonate. water and carbon dioxide are also produced. in the reaction of 398 g HI and 318 g KHCO3, how many grams of KI are produced?

Answer 1

1. This is a limiting reagent problem.
2 Write the equation and balance it.
3a. Convert g HI and g KHCO3 to moles. moles = grams/molar mass.
3b. Using the coefficients in the balanced equation, convert moles HI and moles KHCO3 to moles KI.
3c. You will obtain two answers for moles KI. Obviously both can't be correct. The SMALLER number of moles is the correct answer and it will identify the limiting reagent.
4. Using the smaller number of moles KI from step 3c, convert moles to grams. grams = moles x molar mass.
Post your work if you get stuck.