In a balanced nuclear reaction involving the decay of polonium (Po-212) releasing an alpha particle (\(\alpha\)), we can determine the atomic number of the resulting element (lead in this case) by applying the rules of alpha decay.
An alpha particle consists of 2 protons and 2 neutrons. Thus, when polonium emits an alpha particle, its atomic number decreases by 2.
Polonium has an atomic number of 84. After releasing an alpha particle:
\[ 84 - 2 = 82 \]
Therefore, the atomic number of the resulting element (lead) is 82.
So the correct response is:
82