the line through R and Q is
(y-4)/(x-6) = (3-4)/(4-6)
or
y = x/2 + 1
so, for (-2,b) to be on the same line,
b = -2/2 + 1 = 0
Points R=(6,4), Q=(4,3), and P=(-2,b) are collinear. What is the value of b?
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