Points R=(6,4), Q=(4,3), and P=(-2,b) are collinear. What is the value of b?

Answer 1

the line through R and Q is

(y-4)/(x-6) = (3-4)/(4-6)
or
y = x/2 + 1

so, for (-2,b) to be on the same line,

b = -2/2 + 1 = 0

Answer 2

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