Points A and C on a map are 12 km apart if you follow a certain path. A troop of Boy Scouts leaves Point A at 11:00 a.m. They travel 3 km/hr because they have heavy packs until they reach Point B at 12:45. If they want to reach Point C by 2:00, how fast will they have to go in km/hr?

5 answers

11:00 - 12:45 is 1 3/4 or 7/4 hours.
At 3 km/hr, that means they went

3 * 7/4 = 21/4 km
The remaining distance is thus 12 - 21/4 = 25/4 km

They only have 5/4 hrs left, so since speed = distance/time, they must travel at

(25/4)km / (5/4)hr = 5 km/hr

Sure hope they ate all their food to lighten their packs ...
noice
is dat china
What's the team average speed from point a to c
12 - 21/4 = 27/4

(27/4)km / (5/4)hr = 5.4km/hr

Final answer is 5.4km/hr