The problem can be represented by a triangle with a base equal to 1000 m and
base angles A and B. The 3rd angle is C.
A = 90o-32o = 58o.
B = 90o-64o = 26o.
C = 180-58-26 = 96o.
c/sinC = a/sinA.
1000/sin96 = a/sin58
Multiply bothsides by sin58:
a = 1000*sin58/sin96 = 853 m.
b/sinB = c/sinC.
b/sin26 = 1000/sin96
b = 1000*sin26/sin96 = 441 m.
Side b represents the shortest dist.
from highway to Tower C.
Points A and B 1000 meter apart are plotted on a straight highway running east and west. from A, the bearing of tower C is N32*W and from be, the bearing of C is N64*E. approximate the shortest distance of the tower from the highway.
please explain........
6 answers
PUTANGINAYO WALANG SAGOT SA TANONG KUNG BAKIT SIYA MAHALAGA
Ikaw dennis, wala kang halaga sa mundo.
dennis yung titi mo , supot ... hehe
Bakit wala yung sagot? sure na yan?
373.81 m