To find the dimensions of the original photo before dilation, we will use the scale factor of the dilation. In this case, the dilation is represented by \( D_{Q, 4} \), which means we are dilating by a scale factor of 4.
Given the dimensions of the enlarged poster (the dilated rectangle):
- Length of \( H' I' \) (which corresponds to the original width) = 32 inches
- Length of \( I' J' \) (which corresponds to the original height) = 24 inches
To find the original dimensions, we need to divide the dimensions of the enlarged poster by the scale factor:
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For the length: \[ \text{Original length} = \frac{\text{Dilation length}}{\text{scale factor}} = \frac{32}{4} = 8 \text{ inches} \]
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For the height: \[ \text{Original height} = \frac{\text{Dilation height}}{\text{scale factor}} = \frac{24}{4} = 6 \text{ inches} \]
So, the dimensions of the original photo are \( 8 \text{ inches} \times 6 \text{ inches} \).
From the options given:
- 3 × 8
- 6 × 8
- 12 × 16
- 18 × 24
The closest matching answer to the original dimensions is 6 × 8.