If Point D and Point F have the same second coordinate, we can denote the second coordinate as y. Let's say the x-coordinate of Point D is a.
Since the length of line segment FD is 2 cm, the x-coordinate of Point F should be a + 2 (to the right of Point D by 2 units).
Therefore, the coordinates of Point F would be (a + 2, y).
Point D and Point F have the same second coordinate, and ECFD is a quadrilateral. What coordinates would Point F be plotted at to make line segment FD have a length of 2 cm?
5 answers
yeah but
one is the answer has to be
A ( 1 -1)
(-1, 1)
(-1 0)
(-1 0)
one is the answer has to be
A ( 1 -1)
(-1, 1)
(-1 0)
(-1 0)
If Point D has coordinates (1, -1) and the length of line segment FD is 2 cm, then the coordinates of Point F can be calculated as follows:
Since Point D is at (1, -1), to make the line segment FD 2 cm long, Point F should be 2 units to the left of Point D along the x-axis. Therefore, the coordinates of Point F would be (-1, -1).
So the correct answer should be (-1, -1).
Since Point D is at (1, -1), to make the line segment FD 2 cm long, Point F should be 2 units to the left of Point D along the x-axis. Therefore, the coordinates of Point F would be (-1, -1).
So the correct answer should be (-1, -1).
no ( 1 -1)
(-1, 1)
(-1 0)
(-1 0)
(-1, 1)
(-1 0)
(-1 0)
Apologies for the confusion in the previous response.
Given that Point D has coordinates (1, -1) and Point F has the same second coordinate but is 2 units to the left of Point D to make line segment FD have a length of 2 cm, the correct coordinates of Point F would indeed be (-1, -1).
So, the correct answer should be (-1, -1).
Given that Point D has coordinates (1, -1) and Point F has the same second coordinate but is 2 units to the left of Point D to make line segment FD have a length of 2 cm, the correct coordinates of Point F would indeed be (-1, -1).
So, the correct answer should be (-1, -1).