Point $C$ is the midpoint of $\overline{AB}$, point $D$ is the midpoint of $\overline{AC}$, point $E$ is the midpoint of $\overline{AD}$, and point $F$ is the midpoint of $\overline{AE}$. If $AF=3$, what is the number of units in the length of $\overline{AB}$?

Answer 1

AF=3
AE=6
AD=12
...
and so on till you get to AB

Answer 2

Hi, I’m having a little trouble with math right now. Anyone willing to help me solve the problem above? Please? Thank you. And @Oobleck, I appreciate the effort you’re giving us so we can solve the rest on our own. Thank you. And for the other people that is struggling a little bit just like me, here’s a tip.

So if AF=3, and AE=6 and AD=12, you kind of see the pattern, right? 3, 6, and 12. So 3x2=6, and 3x4=12. They all contain 3! I think that’s a close enough hint. Thank you once again @Oobleck for your tips! I very much appreciate it!

I hope my tips help the rest of the students struggling too. 😘

Answer 3

AB is 48 :)

Answer 4

anwer: 83