To find the midpoint of line segment $\overline{AB}$, we can take the average of the coordinates of points $A$ and $B$. Let's call the midpoint $M$.
To find the $x$-coordinate of $M$, we average the $x$-coordinates of $A$ and $B$. The $x$-coordinate of $A$ is $3$ and the $x$-coordinate of $B$ is $8$, so the $x$-coordinate of $M$ is $\frac{3+8}{2} = \frac{11}{2}$.
To find the $y$-coordinate of $M$, we average the $y$-coordinates of $A$ and $B$. The $y$-coordinate of $A$ is $4$ and the $y$-coordinate of $B$ is $-4$, so the $y$-coordinate of $M$ is $\frac{4+(-4)}{2} = 0$.
Therefore, the midpoint $M$ of line segment $\overline{AB}$ is $\left(\frac{11}{2}, 0\right)$.
Point
\[\blue{A}\] is at
\[\blue{(3, 4)}\] and point
\[\green{B}\] is at
\[\green{(8, -4)}\].
What is the midpoint of line segment
\[\overline{AB}\]?
1 answer