Point

Question

A is at
-3, -5 and point
B is at
2, 5
What is the midpoint of line segment

AB?

Answer 1

The midpoint of line segment AB is found by taking the average of the x-coordinates and the average of the y-coordinates of points A and B.

The x-coordinate of the midpoint is: (2 + (-3)) / 2 = -1/2
The y-coordinate of the midpoint is: (5 + (-5)) / 2 = 0

So, the midpoint of line segment AB is at (-1/2, 0).

Answer 2

Point
\[\blue{A}\] is at
\[\blue{(-3, -5)}\] and point
\[\green{B}\] is at
\[\green{(2, 5)}\].
What is the midpoint of line segment

\[\overline{AB}\]?

Answer 3

To find the midpoint of line segment AB, we need to average the x-coordinates and the y-coordinates of points A and B.

The x-coordinate of point A is -3, and the x-coordinate of point B is 2. To find the average, we add -3 and 2 together and divide by 2:
\[\frac{(-3 + 2)}{2} = -\frac{1}{2}\]

The y-coordinate of point A is -5, and the y-coordinate of point B is 5. To find the average, we add -5 and 5 together and divide by 2:
\[\frac{(-5 + 5)}{2} = \frac{0}{2} = 0\]

Therefore, the midpoint of line segment AB is \[\left(-\frac{1}{2}, 0\right)\].