Point A is 15 miles directly north of point B. From point A, point C is on a bearing of 129°25', and from point B the bearing of C is 39°25'. Find a) the distance between A and C and b)the distance between B and C.

Answer 1

Draw a diagram We see that

<B = 50°35'
<A = 61°35'
so, <C = 57°50'

so, using the law of sines,

AC/sinB = BC/sinA = 15/sinC

So, just plug in the values for the angles.