point (-3, 8) is on the graph y=f(x)

find the new point on:

y = f(x - 2) -3

Similar Questions
    1. answers icon 1 answer
  1. let f be the functionf(x) = x^3 + 3x^2 - x + 2 a. the tangent to the graph of f at the point P = (-2,8) intersects the graph of
    1. answers icon 2 answers
  2. The function f is defined byf(x) = x^3 - x^2 - 4x + 4 The point (a,b) is on the graph of f and the line tangent to the graph at
    1. answers icon 0 answers
  3. The function f is defined byf(x) = x^3 - x^2 - 4x + 4 The point (a,b) is on the graph of f and the line tangent to the graph at
    1. answers icon 1 answer
more similar questions