(Eggs) * (Price) = 240
(Eggs + 24) * (Price - 0.5) = 240
do you know simultaneous equations?
if not, it's OK
first, solve each equation above for Price
then, set those two results equal to each other
the solve that one remaining equation for Eggs
plz plz I need this immediately
"a man sold his stack of eggs for Rs.240.if he had 2 dozen more ,he would have got the same money by selling the whole of 0.5 per dozen cheaper.how many dozen eggs does he sell?"(solution)
5 answers
SORRY . . . think I told you wrong
try this instead
(Eggs) * (Price) = 240
(Eggs + 2) * (Price - 0.5) = 240
first, solve each equation above for Price
then, set those two results equal to each other
the solve that one remaining equation for Eggs
try this instead
(Eggs) * (Price) = 240
(Eggs + 2) * (Price - 0.5) = 240
first, solve each equation above for Price
then, set those two results equal to each other
the solve that one remaining equation for Eggs
I still not got the condition plz explain...
Eggs) * (Price) = 240
(Eggs + 2) * (Price - 0.5) = 240
first, solve each equation above for Price
Eggs) * (Price) = 240
(Eggs + 2) * (Price - 0.5) = 240
first, solve each equation above for Price
OK
from your initial problem statement you have this:
Let D be the number of dozens of eggs the man actually sold.
He was paid Rs240 for D dozens of eggs - right?
So far, we have this first equation:
(1): D * (Price) = Rs240
Next, the problem states that if the man had sold 2 dozen more eggs (that would be D + 2), he would have been paid the same amount (that's Rs240) even if he reduced Price by Rs0.5 per dozen. That information gives us a second equation:
(2): (D + 2) * (Price – 0.5) = Rs240
Now we use the two equations together like this:
(1): Solve D * (Price) = Rs240 for Price
Price = Rs240/D << WE WILL USE THIS BELOW >>
(2): Solve (D + 2) * (Price – 0.5) = Rs240 for Price
(D * Price) + (2 * Price) – (D * 0.5) – (2 * 0.5) = Rs240
(D + 2) * Price – 0.5D – 1 = Rs240
Price = (Rs240 + 0.5D + 1)/(D + 2)
Now use the solution we found above
Since Price = Price (ALWAYS), we obtain:
Rs240/D = (Rs240 + 0.5D + 1)/(D + 2)
Now solve this last equation for D.
from your initial problem statement you have this:
Let D be the number of dozens of eggs the man actually sold.
He was paid Rs240 for D dozens of eggs - right?
So far, we have this first equation:
(1): D * (Price) = Rs240
Next, the problem states that if the man had sold 2 dozen more eggs (that would be D + 2), he would have been paid the same amount (that's Rs240) even if he reduced Price by Rs0.5 per dozen. That information gives us a second equation:
(2): (D + 2) * (Price – 0.5) = Rs240
Now we use the two equations together like this:
(1): Solve D * (Price) = Rs240 for Price
Price = Rs240/D << WE WILL USE THIS BELOW >>
(2): Solve (D + 2) * (Price – 0.5) = Rs240 for Price
(D * Price) + (2 * Price) – (D * 0.5) – (2 * 0.5) = Rs240
(D + 2) * Price – 0.5D – 1 = Rs240
Price = (Rs240 + 0.5D + 1)/(D + 2)
Now use the solution we found above
Since Price = Price (ALWAYS), we obtain:
Rs240/D = (Rs240 + 0.5D + 1)/(D + 2)
Now solve this last equation for D.
Good Sir thanks a lot