Plutonium-239 is a radioactive isotope frequently employed as nuclear reactor fuel, with a half-life of 24,100 years. Approximately how much time would be required for 504 grams of plutonium-239 to undergo decay, leaving only 63 grams of plutonium-239 behind?(1 point)

Responses

24,100 years
24,100 years

72,300 years
72,300 years

96,400 years
96,400 years

48,200 years

1 answer

To determine how long it takes for 504 grams of plutonium-239 to decay to 63 grams, we can use the concept of half-lives.

  1. Calculate how many half-lives it takes to go from 504 grams to 63 grams.

Starting amount = 504 grams Final amount = 63 grams

To find the number of half-lives (n) that have occurred, we can use the formula:

\[ \text{Final amount} = \text{Initial amount} \times \left(\frac{1}{2}\right)^n \]

Plugging in the known values:

\[ 63 = 504 \times \left(\frac{1}{2}\right)^n \]

Dividing both sides by 504:

\[ \frac{63}{504} = \left(\frac{1}{2}\right)^n \]

Simplifying the fraction:

\[ \frac{63}{504} = \frac{1}{8} \]

Now we need to express \(\frac{1}{8}\) as a power of \(\frac{1}{2}\):

\[ \frac{1}{8} = \left(\frac{1}{2}\right)^3 \]

Thus, we can see that \(n = 3\).

  1. Now, we need to find the total time for these 3 half-lives:

Since the half-life of plutonium-239 is 24,100 years, the total time for 3 half-lives is:

\[ 3 \times 24,100 \text{ years} = 72,300 \text{ years} \]

Thus, it would take 72,300 years for 504 grams of plutonium-239 to decay to 63 grams.

The answer is 72,300 years.