find r by dividing any term by the previous term: r = 9/36 = 1/4
So, Tn = 36*(1/4)^(n-1) = 144/4^n
T10 = 144/4^10
This was pretty straightforward. Looks like you need to review the topic.
pls pls help out
A geometric sequence begins
36, 9, 9/4, 9/16, 9/64, . . . .
(a) Find the common ratio r for this sequence.
r =
(b) Find a formula for the nth term an of the sequence.
an =
(c) Find the tenth term of the sequence.
a10 =
1 answer
1 answer