pls...help, QUESTION = At what depth below the free surface of oil having a density of 600kg/m^3 will the pressure be equal to 1bar.

Answer 1

P = ρgh
where
P = pressure (in Pa)
g = acceleration due to gravity = 9.8 m/s^2
h = height (in meters)

Note that 1 bar = 100000 Pa. Substituting,
100000 = (600)(9.8)(h)
h = ?

Hope this helps~ `u`

Answer 2

very well,thank