Pls help pls help me solve. Dry steam at 100 degree Celsius is bubbled into 500 g of water originally at 20 degree Celsius. What will be the temperature of the water after 30 g of steam has condensed? ( specific heat capacity of water =4200,specific latent heat of steam =2260000

4 answers

sum of heats absorbed is zero.
30*2260000 +30(4200)(tf-20)-500(tf-20)=0
bob...how about the 100degrees celcius
Pls solve
I no know abeg.