To plot √(2) and \sqrt[3]{2} on the decimal number line, we need to find their approximate decimal values.
√(2) ≈ 1.4142
\sqrt[3]{2} ≈ 1.2599
Now, comparing the two values:
1.4142 > 1.2599
Therefore, √(2) is greater than \sqrt[3]{2}.
plot 3- √2 and \sqrt[3]{2} on the decimal number line.
Based on your answer above, compare and using <, >, or =.
\sqrt[3]{2} and 3- √2
1 answer