Recall that (cot u)' = -csc² u
Let u = 2x
Then you have ∫-½du = -½u = -½cot u = -½cot x²
pleeeeeeas help meeee
i used an online integral calculator and got an answer which says -1/2cot(x^2) but i don't know how to get there. the problem is "integral{xcsc^2(x^2)}
3 answers
Oops u = x²
mumble mumble. Bad notation, but you see the steps.