The cover the same distance, in the same time.
You have two equations, one for the police car (starting from rest)
the other the speeder.
set each distance equal, solve for time.
then solve for distance.
Please solve and answer. Need done ASAP.
A speeder passes a parked police car at 35.0 m/s. The police car starts from rest with a uniform acceleration of 2.39 m/s2.
(a) How much time passes before the speeder is overtaken by the police car? __ s
(b) How far does the speeder get before being overtaken by the police car?
1 answer
1 answer