oxalic is monoprotic, so
N=moles/volume=(6.3/63)/.5
Please sir solve this...
6.3 gm of oxalic acid (eq. Wt.=63) is dissolved in 500 ml solution what will be the normality of the solution?
2 answers
I don't believe H2C2O4 has an equivalent weight of 63. The molar mass is 90 and it is diprotic; therefore, the equivalent weight is 45.