Please Simplify:

Question

(1/8)(40v−24y)−(1/7)(21v−35y+9)−(1/6)

(1/11)(55x−22)−(1/2)(18x−2v)

Answer 1

start with the parens:

(1/8)(40v−24y) = 5v-3y
(1/7)(21v−35y+9)−(1/6) = 3v-5y + 9/7 - 1/6

Now subtract to get
2v+2y - 47/42

do the other the same way