2NaOH + H2SO4 ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = about 0.02 but that's only approximate. The look at the equation; mols NaOH = twice that or about 0.05 mols in the 20.00 mL (20.00 mL = 0.02L)
So (NaOH) = about 0.05mol/0.02L = ?M
Please show me step by step. Thank you.
One commercial method used to peel potatoes is to soak them in a solution of NaOH for a short time, remove them from the NaOH, and spray off the peel. The concentration of NaOH is normally in the range of 3 to 6 M. The NaOH is analyzed periodically. In one such analysis, 45.7 mL of 0.500 M H2SO4 is required to neutralize a 20.0-mL sample of NaOH solution. What is the concentration of the NaOH solution?
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