please show me in steps how to solve this

Question

thanks alot!

A bobsled zips down an ice track, starting from rest at the top of a hill with a vertical height of 150m. Disregarding friction, what is the velocity of the bobsled at the bottom of the hill? (g=9.81 m/s^2)

any help is appreciated :)

Answer 1

loss of potential energy = kinetic energy at bottom
m g h = (1/2) m v^2
9.81 * 150 = (1/2) v^2
solve for v

Answer 2

54.2