15 is less than 900
so it cannot come later in the sequence if the ratio is greater than 1.
Please...I really need help on this question...Thanks.
-Noah is trying to create a sequence for his group. He wants the common ratio to be 4, he wants the 5th term to be 15 and he wants the 8th term to be 900. However, this is NOT possible! Explain to Noah why it is not possible create the sequence he has in mind.
3 answers
oops.
900/15 is not a power of 4
900/15 is not a power of 4
so you know r = 4
term5 = ar^4 = 15
term8 = ar^7 = 900
divide one by the other: ar^7/(ar^4) = 900/15
r^3 = 60
clearly r ≠ 4
could have worked if term8 = 960
term5 = ar^4 = 15
term8 = ar^7 = 900
divide one by the other: ar^7/(ar^4) = 900/15
r^3 = 60
clearly r ≠ 4
could have worked if term8 = 960