After seeing how you responded to Steve when he helped you with this question ....
http://www.jiskha.com/display.cgi?id=1479505703
Please I need help with this algebra problem
With the 3 equations
f1(x)=0
f2(x)=1/8(x+16)^2-98
f3(x)=2x+24
Determine an equation for this function with the 3 pieces above.(Refer to creating the polynomial functions)
I do not know how does everyone get this answer g(x) = f2(x)-f3(x)
= (1/8(x+16)^2-98)-(2x+24)
= 1/8 x^2 + 2x - 90
3 answers
The g(x) I suggested was a last-ditch effort to come up with some function using f1,f2,f3. You repeatedly refused to specify what you meant when you said
Determine an equation for this function
"this function" indicates that there is some function you want to create using f1,f2,f3. But you never say what it is; I made one up, just to illustrate how to use them. If you have some other function, we'll be happy to help with its derivation.
Just as a final effort to be helpful, despite your intransigence,
(1/8(x+16)^2-98)-(2x+24)
= 1/8 (x^2+32x+256) - 98 - 2x - 24
= 1/8 x^2 + 4x + 32 - 98 - 2x - 24
= 1/8 x^2 + 2x + 90
You really need to do some of the work on your own, rather than just sulking when the entire solution is not provided.
Determine an equation for this function
"this function" indicates that there is some function you want to create using f1,f2,f3. But you never say what it is; I made one up, just to illustrate how to use them. If you have some other function, we'll be happy to help with its derivation.
Just as a final effort to be helpful, despite your intransigence,
(1/8(x+16)^2-98)-(2x+24)
= 1/8 (x^2+32x+256) - 98 - 2x - 24
= 1/8 x^2 + 4x + 32 - 98 - 2x - 24
= 1/8 x^2 + 2x + 90
You really need to do some of the work on your own, rather than just sulking when the entire solution is not provided.
Did Steve's additional explanation help you?