for the rabbit question, t=12 (one year), so y=260(2.7)^((0.06)(12))
=534.15
I will do the last one for you
r/n = .16/4 = .04
nt = 2*4 = 8
Amount = 700(1.04)^8
=$958.00
Please help with my word problems?
Solve the problem.
The rabbit population in a forest area grows at the rate of 6% monthly. If there are 260 rabbits in April, find how many rabbits (rounded to the nearest whole number) should be expected by next April. Use y=260(2.7)^0.06t? (I don't understand how to solve this problem?)
The size of the beaver population at a national park increases at the rate of 5.1% per year. If the size of the current population is 151, find how many beavers there should be in 4 years. Use the function f(x)=151e^0.051t and round to the nearest whole number. (This is what I got so far: f(4)=151e^0.051t)
Find the accumulated value of an investment of $20,000 at 12% compounded annually for 5 years. (I know annually is once year, so this is over a period of 5 years, so it would be five years and I would have to use the formual a=p(1 +r/n)^nt)
Find the accumulated value of an investment of $700 at 16% compounded quarterly for 2 years
(I know quarterly means 4 times, so if its for 2 years, it would 8 times, and I think the equation I would use would be a=p(1 +r/n)^nt)
3 answers
the problem that is posted above is incorrect. The rabbit population in a forest grows at the rate of 6% monthly. If there are 160 rabbits in April, find how many rabbits should be expected by next April. Use y=160(2.7)^0.06t; t=rate of rabbit population growth;
Step 1: 0.06*(12)= .72
step 2: y=160(2.7)^.72
Step 3: y = 160(2.044475)
Step 4: y = 327.1160=327
Step 1: 0.06*(12)= .72
step 2: y=160(2.7)^.72
Step 3: y = 160(2.044475)
Step 4: y = 327.1160=327
The rabbit population in a forest area grows at the rate of 7% monthly. If there are 220 rabbits in April, find how many rabbits(rounded to the nearest whole number ) should be expected by the next April. Use y= 220(2.7)^0.07t
3 answers