I'm thinking this should be
a=?
b=2
c=6
a^2 -2^2 = 6^2
a^2 = 40
so the equation would be x^2/4 + y^2/40 = 1
Is that correct?
Please help-What is the equation of the ellipse with foci (0,6), (0,-6) and co-vertices (2,0),(-2,0)
Please explain the steps because I have 5 to do for homework-Thank you-I'm really stuck on this
3 answers
That is correct solution.
Could you recheck my answer because I just realized it can't be write-it's not a choice-
could it be x^2/1 +y^2/40 =1 or would it be x^2/1 + y^2/36 = 1
Those were the only two choices
could it be x^2/1 +y^2/40 =1 or would it be x^2/1 + y^2/36 = 1
Those were the only two choices
2 answers