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Please help using identities

(2tan30)/(1-tan^2 30)

3 answers

[sin/cos] / [ 1 - sin^2/cos^2 ]

sin cos / [cos^2-sin^2]

sqrt3/4 / [ 3/4 - 1/4 ]

(1/2) sqrt 3

Remember your double-angle formulas. You have

tan(2*30) = √3

Reiny dropped the 2 in the numerator...

oops, sorry Reiny...

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