Please Help!!

Question

Using heat of fusion, Specific heat, or heat of evaporation.

Calories to condense 135g of steam at 100 degrees C and to cool the liquid to 15 degrees C.
This is how I calculated it using heat of evaporation:

135gx540 cal=72900cal

72900cal/135g x (delta T)85 degrees C= 6.4
I know the correct answer is 8.44 x 10^4
So what did I do wrong?
Thank you!

Answer 1

35gx540 cal=72900cal
This first step is right. 72.9 kcal to condense 135 g steam at 100 C to liquid at 100 C. The error is the next step.
The next step is heat removed to cool liquid water at 100 to 15 C is
135g x 1 cal/g*C x (15-100) = ?
Then add step 1 to step 2 for total heat released.

72900cal/135g x (delta T)85 degrees C= 6.4
I know the correct answer is 8.44 x 10^4