width: w
length: 2w+5
area: w(2w+5) = 33
2w^2 + 5w - 33 = 0
(w-3)(2w+11)
w=3 or -11/2
width: 3
length: 2(3)+5 = 11
of course, that solution would have been suggested by the fact that 33=3*11, without even solving for w.
Please help:
The length of a rectangle is 5m greater than twice its width, and its area is 33m^2 (the m is squared). Find the dimensions.
1 answer