The length of a rectangle is 3 yd less than double the width means:
L = 2 W - 3
A = L ∙ W = ( 2 W - 3 ) ∙ W = 65
2 W ² - 3 W = 65
Subtract 65 to both sides
2 W ² - 3 W - 65 = 0
The solutions are:
W = 13 / 2 = 6.5
and
W = - 5
The width can't be so W = 6.5 yd
L = 2 W - 3 = 2 ∙ 6.5 - 3 = 13 - 3 = 10 yd
A = L ∙ W = 10 ∙ 6.5 = 65 yd ²
PLEASE HELP ?
The length of a rectangle is 3 yd less than double the width, and the area of the rectangle is 65 yd2. Find the dimensions of the rectangle.
2 answers
My typo.
The width can't be NEGTIVE so W = 6.5 yd
The width can't be NEGTIVE so W = 6.5 yd
2 answers