PLEASE HELP ?

Question

The length of a rectangle is 3 yd less than double the width, and the area of the rectangle is 65 yd2. Find the dimensions of the rectangle.

Answer 1

The length of a rectangle is 3 yd less than double the width means:

L = 2 W - 3

A = L ∙ W = ( 2 W - 3 ) ∙ W = 65

2 W ² - 3 W = 65

Subtract 65 to both sides

2 W ² - 3 W - 65 = 0

The solutions are:

W = 13 / 2 = 6.5

and

W = - 5

The width can't be so W = 6.5 yd

L = 2 W - 3 = 2 ∙ 6.5 - 3 = 13 - 3 = 10 yd

A = L ∙ W = 10 ∙ 6.5 = 65 yd ²

Answer 2

My typo.

The width can't be NEGTIVE so W = 6.5 yd