Let's first understand what this kind of question means.
I will do the 3rd one
cos(arctan(3))
arctan(3/1) means the angle Ø so that tanØ = 3/1
so draw a right angles triangle with angle Ø, opposite as 3 and adjacent as 1, ( remember tanØ = opp/adj )
By Pythagoras, the hypotenuse is √10
so cos(arctan(3))
= cos Ø
= 1/√10
Do the first 2 the same way.
PLEASE HELP!!
Solve:
1. cos(arcsin(4/5))= ??
2. tan(arccos(4/5))= ??
3. cos(arctan(3))= ??
Note: Give exact answers!!
3 answers
I got them :). Thank you so much for explaining it really well, my textbook doesn't explain well at all, that's why I was struggling!! Thank you once again!!
You are welcome,
90% of success in math is understanding it
90% of success in math is understanding it
1 answer