Please help set this up-

Question

A person goes into the electric field and has an object with a charge value of 4.2E-6C. At a distance of 10m from the object that's responsible for the elctric field, the person sees a force of 8.0N on the object they have.
What is electric field intensity?
What is electric potential at that point?
I'm totally confused-Would I start with f=kq1/r^2 and I have no idea for the second question-please direct me to at least the correct formula Thank you

Answer 1

E=k*4.2E-6/10^2

assuming it was a point charge causing the field.

V=k*4.2E-6/10

Answer 2

Thank you-I really appreciate this-I can figure it out finally-thanks again