The sum of the heats gained is zero? (some gain, some lose)
HeatgainedbyWater+heatgainedbylead=0
23.4*Cw*(Tf-8.68)+16.6*cpb*(Tf-138)=0
look up the specific heats for water, and lead, then solve for Temp final Tf
PLEASE HELP OR I WILL FAIL
What would be the final temperature of the system if 16.6 g of lead at 138 ◦C is dropped into 23.4 g of water at 8.68 ◦C in an insulated
container? The specific heat of lead is 0.128J/g◦C.
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