Please help me with this WS

1) Find the value of lim as x-->-(square root of 3) of (-x^4 + 5x^2 -6)/(x+(square root of 3)
2) Find the distance between the discontinuities of g(x)= ((square root of x-4))/(x^2 -5x -1)
3)Find the value of x at which the curve y=(x^2 - 4)/(x^5 + 2x^4 + 6x + 12) has a Vertical Asymptote
4)lim as x-->-2 of (1)/(x+2) + (4)/(x^2 -4)
5)The volume of a cube is increasing at the rate of 20 cubic cm per second. How fast, in square cm per second, is the surface area of the cube increasing at the instant when the edge of the cube is 10 cm long?
6)The normal line to the curve y=(square root of 16-x) at the point of (0,4) has a slope of what?

1 answer

-(x^4 - 5 x^2 + 6) / (x +3^.5)

-(x^2-3)(x^2-2) /(x+3^.5) OH LOOK!

-(x-3^.5)(x+3^.5)(x^2-2)/(x+3^.5)

= -(x-3^.5)(x^2-2)
when x is -3^.5

= -(-2*3^.5)(1)
= 2 sqrt 3

Now there is a limit and I am at it without you doing some.
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