I will assume you mean
lim (1 - cosx)/sinx , as x ---> 0
= lim (1 - cosx)/sinx * (1+cosx)/(1+cosx)
= lim (1 - cos^2 x)/(sinx(1+cosx)
= lim sin^2 x/(sinx(1+cosx) , as x ---> 0
= lim sinx/(1+cosx) , as x ---> 0
= 0/2
= 0
Please help me with this question:
lim __1_-_cosx__
x-0 sinx
Thank you!
2 answers
Yes that was the question. Sorry I messed up the structure.
Thanks for your help!
Thanks for your help!